The volume of a cone is pi(r2h)/3 If the radius and height are both tripled, plugging this into the equation gives us pi(3h(3r)2)/3 =pi(3h9r2)/3 =27pi(r2h)/3 which is 27 times the initial volume. Thus if the radius and height of a cone are tripled, the volume multiplies by 27.
The volume of the larger sphere will be 27 times the original. Here's the math: Volume of sphere of radius r is (4/3) x pi x r3 Volume of sphere of radius 3r is (4/3) x pi x (3r)3 or 27r3
V = (pi) R^2 H/3 if radius triples then volume goes as radius squared = 9 times more, so you would need to reduce height by 9 to keep same volume
It will be twice the size of the tripled radius
The answer depends on what is tripled.
it looks like a circle.
The volume of a cone is pi(r2h)/3 If the radius and height are both tripled, plugging this into the equation gives us pi(3h(3r)2)/3 =pi(3h9r2)/3 =27pi(r2h)/3 which is 27 times the initial volume. Thus if the radius and height of a cone are tripled, the volume multiplies by 27.
The volume increases 27-fold.
The original volume is multiplied by 27.
The volume increases to 9 times as much.
A [multiplicative] change in one dimension makes the same change in the volume. So the volume would be tripled.
The new volume is 3^3 = 27 times as much.
If the radius of a sphere is tripled, the surface area increases by (3)2 = 9 times, and the volume increases by (3)3 = 27 times.
If the radius is tripled then the Area will be greater by a factor of 9. And the circumference will be greater by a factor of 3.
The volume of the larger sphere will be 27 times the original. Here's the math: Volume of sphere of radius r is (4/3) x pi x r3 Volume of sphere of radius 3r is (4/3) x pi x (3r)3 or 27r3
V = (pi) R^2 H/3 if radius triples then volume goes as radius squared = 9 times more, so you would need to reduce height by 9 to keep same volume
It will be twice the size of the tripled radius