| 3-i - 1/(3-i)| = | 3-i - (3+i)/10|= | (27-11i)/10| = sqrt(17/2)
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1/(1+ 3i)
3i where i is the square root of negative one.3i x 3i = -9
4
Use the rules of division for complex numbers. Just divide 1 / (4 + 3i). This requires multiplying numerator and denominator of this fraction by (4 - 3i), to get a real number in the denominator.
x2 + 9 = (x + 3i)(x - 3i) The answer is based on a knowledge of imaginary and complex numbers where i2 = -1