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The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
i is the Imaginary Unit, equal to sqrt(-1). So i and any real number multiplied by i will all be imaginary numbers. Here are some: i, -i, 5i, -3i, i*pi, etc.
(3x - 1)(x - 4) so roots are 1/3 and 4
1/(1+ 3i)
The answer to the question, as stated, is that the other root could be anything. However, if all the coefficients of the quadratic equation are real numbers, then the other root is 1 minus 3i.