An object subjected to Earth's gravity of about 32.2 feet per second2 will fall 64.4 feet.
distance = 1/2 At2
velocity = At
At that point, they would be traveling about 44 miles per hour, which is less than terminal velocity of about 125 miles per hour, which means that it does not significantly matter how much the person weighs, because air friction does not really enter into the picture yet.
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(4 meters/second)(40 seconds) = 160 meters.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
Because this is a free fall questions, the equation d=1/2gt² can be used. Gravity is a given, 9.8 m/s² and the time is your 15 seconds of free fall. d=1/2(9.8m/s²)(15s)²= 1,102.5m. To find feet multiply 3.28084 to answer because that is how many feet are in a meter.
In order to come up with an answer, we have to impose a couple of rules: 1). we're trying this on the earth 2). we're ignoring the effects of air 3). it's not moving at the beginning of the 5 seconds ... that's when you drop it from your hand Then the rock falls 400 ft in five seconds. What's really interesting is that it doesn't matter how much it weighs. ALL rocks fall the same distance in 5 seconds.
Assuming free fall in a vacuum, an object will fall approximately 64 meters (210 feet) in 4 seconds, as acceleration due to gravity is 9.81 m/s^2. However, in reality, air resistance would slow down the fall, so the distance would be slightly less. It's important to consider factors such as air resistance, initial velocity, and gravitational acceleration when calculating the distance fallen in a specific timeframe.