We must neglect air resistance, since we don't know anything about the size
or shape of the object that would allow us to calculate air resistance, and also
because even if we had all the data we would not have a clue how to use it to
calculate air resistance.
We'll also assume that this experiment is conducted on or near the Earth's
surface, so that the acceleration of gravity is 9.8 m/s2 .
-- In 10 seconds, the object's downward speed will increase by 98 m/s , and it
will be falling at (98 + 25) = 123 m/s .
-- Its average speed during the 10 seconds is 1/2 of (25 + 123) = 74 m/s .
-- In 10 seconds, at an average speed of 74 m/s , it covers 740 meters.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
The acceleration of gravity is 9.8 meters per second2 .In 3 seconds, gravity increases the falling speed by (9.8 x 3) = 29.4 meters per second.This particular ball already had a downward speed of 6 m/s when the 3 seconds began,so at the end of the 3 seconds, its velocity is(6) + (9.8 x 3) = 35.4 meters per second downward
the answer is 24-9 m/sec. yuor welcome
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
The velocity of the ball will be -30 m/s (downward) after 5 seconds due to gravity.
The acceleration of gravity is 9.8 meters per second2 downward. 1.6 seconds after falling from a branch near the surface of the Earth, the apple's speed is 15.68 meters per second. It's velocity is 15.68 meters per second downward. The tree has to be really tall, since the apple falls 12.544 meters (about 41 feet) in 1.6 seconds.
During the 5 seconds, gravity adds 5G = (5 x 9.78) = 48.9 meters/sec to the object's downward speed.During that time, it's average downward speed is 1/2 of [ Vi + (Vi + 48.9) ] = Vi + 24.45 m/s.In 5 seconds it falls 5(Vi + 24.45) = 5Vi + 122.25 meters.5Vi + 122.25 = 240 meters5Vi = 240 - 122.25 = 117.75 metersVi = 117.75 / 5 = 23.55 meters per sec.
The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Given the initial velocity (A), final velocity (B), and time (8 seconds), you can substitute the values into the formula to find the acceleration.
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
The acceleration of gravity is 9.8 meters per second2 .In 3 seconds, gravity increases the falling speed by (9.8 x 3) = 29.4 meters per second.This particular ball already had a downward speed of 6 m/s when the 3 seconds began,so at the end of the 3 seconds, its velocity is(6) + (9.8 x 3) = 35.4 meters per second downward
the answer is 24-9 m/sec. yuor welcome
An object dropped from rest will have a downward velocity of (9 g) = 88.2 meters per second after 9 seconds. Ignoring air resistance, the mass of the object is irrelevant. All masses fall with the same acceleration, and have the same downward velocity after any given period of time.
The total time of flight for a ball thrown vertically upwards and returning to its starting point is twice the time taken to reach maximum height. Therefore, the time taken to reach maximum height is 4 seconds. Given that the acceleration due to gravity is -9.8 m/s^2, using the kinematic equation v = u + at, where v is the final velocity (0 m/s at maximum height), u is the initial velocity, a is the acceleration due to gravity, and t is the time, you can solve for the initial velocity. Substituting the values, u = 9.8 * 4 = 39.2 m/s. Therefore, the initial velocity of the ball thrown vertically upward is 39.2 m/s.
Since the equation for time=sqrt(2h/g) set 2 seconds for time and 9.8 for gravity so 2=sqrt(2h/9.8) clear the sqrt by squaring both sides 4= 2h/9.8 9.8*4 =2h (9.8*4)/2 = height. now that you have the height, you can do v=distance/time v=height from the equation prior/2 seconds i hope that works..