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How high does a ball go if it is thrown up with an initial speed of 10 meters per second?
Wiki User
∙ 14y ago
applying the equation:
(VxV) -(UXU) = 2aS
on reaching the maximum height the ball stops so the final velocity(V) becomes =0.
initial velocity as given is (U)=10 m/s.
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acceleration is here gravity in downward direction so (a)=-9.81 m/s
so applying the above stated formula the height reached by the ball(S)=5.0968 m
(approx)
Wiki User
∙ 14y ago
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We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
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A ball is thrown straight up with an initial speed of 20 m calculate its initial speed take g10 ms-2?
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How high does the stick go and What is the speed of the stick when it hits the ground if A stick held at a height of 2.50 meters is thrown into the air at 2.00 meters per second?
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How do you answer this physics question?
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
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-- Your speed after 30 seconds will be 30 meters per second.-- Since your acceleration is constant, your average speed during the 30 secondsis the average of your initial and final speed . . . 15 meters per second.-- The distance you cover is your average speed for 30 seconds = 15 x 30 = 450 meters.
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The speed at which a ball hits the ground will depend on the initial speed it was thrown with, the angle at which it was thrown, and the effects of air resistance. In ideal conditions, if air resistance is neglected, the speed at impact will be the same as the speed at which it was released when it reaches the ground.
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