applying the equation:
(VxV) -(UXU) = 2aS
on reaching the maximum height the ball stops so the final velocity(V) becomes =0.
initial velocity as given is (U)=10 m/s.
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acceleration is here gravity in downward direction so (a)=-9.81 m/s
so applying the above stated formula the height reached by the ball(S)=5.0968 m
(approx)
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
1000000 m
-- Your speed after 30 seconds will be 30 meters per second.-- Since your acceleration is constant, your average speed during the 30 secondsis the average of your initial and final speed . . . 15 meters per second.-- The distance you cover is your average speed for 30 seconds = 15 x 30 = 450 meters.
Its initial speed cannot be 20 m, as stated in the question. Secondly, if the initial speed is correctly given, then there is no need to calculate it!
so you calculate for one second howmuch meters do you pass and the number that you had is your speed on meters per second
Ignoring air resistance, its horizontal speed is still 9 meters per second, its vertical speed is approx. 9.81 m/s, as the acceleration of gravity is 9.81 meters per second per second.
After a second, the ball will still have a horizontal velocity of 8 meters per second. It will also have a vertical velocity of 9.8 meters per second (Earth's acceleration is about 9.8 meters per square second). The combined speed (using the Law of Pythagoras) is about 12.65 meters per second.
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
Whether the object is dropped, thrown downwards, thrown upwards, or thrown horizontally, its downward acceleration is the same 9.8 meters per second2. If it's thrown downwards, however, its speed at any instant is greater than the speed at the same instant would be if it had only been dropped, since it has some speed before the acceleration begins.
The answer is 32 meters
Average acceleration over an interval of time = (final speed - initial speed) / (time for the change)= [ (0 - 30) / 1 ] (meters / second-minute) = [ (0 - 30) / (60) ] (meters / second-second) =-0.5 meter / sec2
1000000 m
-- Your speed after 30 seconds will be 30 meters per second.-- Since your acceleration is constant, your average speed during the 30 secondsis the average of your initial and final speed . . . 15 meters per second.-- The distance you cover is your average speed for 30 seconds = 15 x 30 = 450 meters.
A ball is thrown vertically upward with an initial speed of 20m/s. Two second later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24m/s. At what height above the release point will the ball and stone pass each other?
The speed of the baseball can be calculated using the formula: speed = distance / time. Plugging in the values, we get speed = 20 meters / 0.5 seconds = 40 meters per second. Thus, the speed of the baseball is 40 m/s.
Its initial speed cannot be 20 m, as stated in the question. Secondly, if the initial speed is correctly given, then there is no need to calculate it!
The answer depends on how high the ball is thrown and at what angle. If the ball is thrown on Earth, Earth's gravity has objects fall at an increasing rate of 32 feet per second per second. This means that an object will go 32 feet per second faster every second it is falling down in the air. So, the higher the ball is in the air, the faster it goes as it is about to hit the ground.