The tangent ratios are equal so let the height of the tree be x:
x/33 = 7/6
Multiply both sides 33:
x = 231/6 = 38.5
Height of tree = 38.5 units of measurement.
40 ft
50 feet
5.5/8 = x/20 x=5.5*20/8 = 13.75 feet
17.45 feet.
3
50 feet
40 ft
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
3.4
The shadow:object ratio is 1:1 so the tree is 63 feet high.
Not enough information has been given to solve this problem such as: What is the angle of elevation?
If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.Put 27/18 and 63/x.Cross multiply, get 27x=1134Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
5.5/8 = x/20 x=5.5*20/8 = 13.75 feet
17.45 feet.
It is approx 36.6 ft.
(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2
28 feet