The underlying supposition, namely that -2 > 0, is incorrect. 0 is a more positive quantity than -2 and would be considered "larger".
The only way that -2 would be considered "greater" than 0 is if the numbers are being evaluated for their magnitude or absolute value. Since the magnitude or absolute value of a number is the same number but with a positive sign in all cases, |-2| IS > 0 because 2 > 0.
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In the context of integers, negative 5 is greater than negative 6. This is because as we move to the left on the number line, the numbers decrease. So, negative 5, which is closer to zero, is greater than negative 6, which is further to the left. Negative 5 is one unit closer to zero than negative 6, making it the greater of the two values.
If you consider only the magnitude of the two numbers (disregarding the signs) then 6 is greater than 3. But when we have signed numbers, we have to imagine the number line. On the negative side of zero, a negative number closer to zero is considered greater than a negative number that is farther from zero. Similarly on the positive side of zero, a positive number closer to zero is considered smaller than a positive number that is farther from zero. I hope that explains it. -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
No it is not
Negative two thirds is smaller than negative one sixth. To have more of a negative is to have less.
No. Their product is always greater than 0.