It could be the area formula for a rectangle which is: area = length times width
To express the statement "length is 4 times the width plus 4" as a formula, you can define the width as ( w ) and the length as ( l ). The formula can then be written as: [ l = 4w + 4. ] This equation indicates that the length (( l )) is equal to four times the width (( w )) plus four.
L = 267
the formula of area is l*w or length (times) or ''x'' width
the formula for the perimeter of a rectangle is p = 2W + 2L, where L is the length and W is the width, so your first equation is 126 = 2W + 2L"twice as long as it is wide" means that the length L is 2 times the width W, so your second equation is L = 2WIn order to solve for the dimensions, you can substitute L for 2W in the first equation to get:126 = L + 2L126 = 3LL = 126/3L = 42and because L = 2W:42 = 2WW = 42/2W = 21
Nothing. There is no l in the equation.
its a equation
To express the statement "length is 4 times the width plus 4" as a formula, you can define the width as ( w ) and the length as ( l ). The formula can then be written as: [ l = 4w + 4. ] This equation indicates that the length (( l )) is equal to four times the width (( w )) plus four.
L = 267
The perimeter is the total length of the two equal lengths ,L, and the two equal widths ,W,. So the formula is: 600 = 2L + 2W . The other information is put in equation form as: L = 3W + 2. So here you have two eqations in the two unknowns L & W. Use your algebra skills to solve these equations simultaneously to find the unknowns. Once you know L & W then you can find the area(if you want) from the area formula ; A = LW .
You need to show the equation. It makes a difference.
it is the volume
No, mass times acceleration does not equal velocity squared dimensionally. The dimensional equation for mass times acceleration is [M][L][T]^-2, while the dimensional equation for velocity squared is [L]^2[T]^-2. These are not equivalent dimensions.
the formula of area is l*w or length (times) or ''x'' width
the formula for the perimeter of a rectangle is p = 2W + 2L, where L is the length and W is the width, so your first equation is 126 = 2W + 2L"twice as long as it is wide" means that the length L is 2 times the width W, so your second equation is L = 2WIn order to solve for the dimensions, you can substitute L for 2W in the first equation to get:126 = L + 2L126 = 3LL = 126/3L = 42and because L = 2W:42 = 2WW = 42/2W = 21
area or square and rectangle.
Length times length (at right angles) ... or width x breath.
To solve for H in the equation A = L x W x H, you need to isolate H on one side of the equation. To do this, divide both sides of the equation by (L x W) to solve for H. The formula for solving for H would be H = A / (L x W). This formula allows you to calculate the height (H) when given the area (A), length (L), and width (W) of a rectangular object.