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Given that (7-6) is on the graph f(x) find the corresponding point for the function f(x plus 2)?
When the x coordinate is changed by adding a constant amount this is the same as translating (shifting) the graph of the function f(x) that amount parallel to the x-axis; if the amount is positive the graph is translated to the left, if it is negative it is translated to the right. As (7, -6) is on f(x), then under the translation f(x + 2), the graph is translated to the left (2 x-values), so the point (7-2, -6) which is the point (5, -6) is the corresponding point on the graph to (7, -6).
y= log base b(x-h) +k?
The graph of log base b(x-h)+k has the following characteristics. the line x = h is a vertical asymptote; the domain is x>h, and the range is all real numbers; if b>1, the graph moves up to the right. of 0>b>1, the the graph moves down to the right.
What is the answer to Log x plus 4 minus log6 equals 1?
log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006
Would the graph of y equals x squared be a straight line on log paper?
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What is the inverse of Y equals 6 plus logx?
You have, y = 6 + log x anti log of it, 10y = (106) x
Given that (7-6) is on the graph f(x) find the corresponding point for the function f(x plus 2)?
When the x coordinate is changed by adding a constant amount this is the same as translating (shifting) the graph of the function f(x) that amount parallel to the x-axis; if the amount is positive the graph is translated to the left, if it is negative it is translated to the right. As (7, -6) is on f(x), then under the translation f(x + 2), the graph is translated to the left (2 x-values), so the point (7-2, -6) which is the point (5, -6) is the corresponding point on the graph to (7, -6).
What is the answer to log x6?
log(x6) = log(x) + log(6) = 0.7782*log(x) log(x6) = 6*log(x)
Log x - log 6 equals log 15?
log(x) - log(6) = log(15)Add log(6) to each side:log(x) = log(15) + log(6) = log(15 times 6)x = 15 times 6x = 90
How will the graph of log x compare to the graph of ln x?
They both pass through the point (1,0) and have the same general shape. The log(x) curve is less steep than ln(x).
What describes how to translate the graph y x to obtain the graph of y x - 6?
To translate the graph y = x to the graph of y = x - 6, shift the graph of y = x down 6 units.
If f(x) is the graph of f(x) translated down 2 units?
f(x) cannnot be a graph of itself translated down by anything other than 0 units.
y= log base b(x-h) +k?
The graph of log base b(x-h)+k has the following characteristics. the line x = h is a vertical asymptote; the domain is x>h, and the range is all real numbers; if b>1, the graph moves up to the right. of 0>b>1, the the graph moves down to the right.
What is the answer to Log x plus 4 minus log6 equals 1?
log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006
Log x plus 7 equals 1 plus Log x-1?
logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999
Which statement correctly describes the graph of g(x) if g(x) f(x - 6)?
The graph of g(x) is the graph of f(x) shifted 6 units in the direction of positive x.
What is the graph of the equation y x translated 4 units up?
Y = x + 4
Would the graph of y equals x squared be a straight line on log paper?
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