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The graph of log base b(x-h)+k has the following characteristics. the line x = h is a vertical asymptote; the domain is x>h, and the range is all real numbers; if b>1, the graph moves up to the right. of 0>b>1, the the graph moves down to the right.
What else can I help you with?
What is the definition of log?
log base m of x = y is equivalent to x=m^y
How do you calculate the exponent y if the base is 2 and the answer is 50?
If 2y = 50 then y*log(2) = log(50) so that y = log(50)/log(2) = 5.6439 (approx). NB: The logarithms can be taken to any base >1.
Solve ln y equals xln e?
ln is the natural logarithm. That is it is defined as log base e. As we all know from school, log base 10 of 10 = 1 just as log base 3 of 3 = 1, so, likewise, log base e of e = 1 and 1.x = x. so we have ln y = x. Relace ln with log base e, and you should get y = ex
If log y equals 0.7 plus 2 times log x express y in terms of x?
It cannot be done because the base for the second log is not given.
What is the inverse of y equal the log of 2x?
y = log 2x → x = 1/2 <base of log>y So: y = log102x → x = 1/210y (common logs) y = loge2x → x = 1/2ey (natural logs)
What is the definition of log?
log base m of x = y is equivalent to x=m^y
What is the untiderivative of k to the power of x?
If in the real number universe, first k is to be >0, y=kx = exlog(k) the antiderivative of eax is eax/a so the antiderivative of Y is exlog(k) / log(k) = kx /log(k)
How do you calculate the exponent y if the base is 2 and the answer is 50?
If 2y = 50 then y*log(2) = log(50) so that y = log(50)/log(2) = 5.6439 (approx). NB: The logarithms can be taken to any base >1.
If y equals 10 then what is then what is y equals log x?
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
Solve ln y equals xln e?
ln is the natural logarithm. That is it is defined as log base e. As we all know from school, log base 10 of 10 = 1 just as log base 3 of 3 = 1, so, likewise, log base e of e = 1 and 1.x = x. so we have ln y = x. Relace ln with log base e, and you should get y = ex
If log y equals 0.7 plus 2 times log x express y in terms of x?
It cannot be done because the base for the second log is not given.
Why can't the base on logarithms be one?
let's look at log base 2 (x)=8, that means 2^x=8 so x=3 in general if b^y=x, then log base b (x)=y if the base is 1, then we have 1^y=x, but 1^y=1 for all y so it does not work..
What is the inverse of y equal the log of 2x?
y = log 2x → x = 1/2 <base of log>y So: y = log102x → x = 1/210y (common logs) y = loge2x → x = 1/2ey (natural logs)
Logarithm of y with base b?
Let b and y be positive numbers, b can't be 1. log base b y = x if and only if b^x=y
How do you use logarithm tables for division?
Suppose you want to divide x by y Find log(x) and log(y) to any base b (usually 10 or e) Calculate z = log(x) - log(y) Look up the antilog of z (or find the number whose log is z). x/y = antilog(z)
The log of a quotient is the log of a numerator divided by the log of the denominator?
For a quotient x/y , then its log is logx - log y . NOT log(x/y)
How do I solve the equation e to the power of x equals 2 using logarithms?
When the logarithm is taken of any number to a power the result is that power times the log of the number; so taking logs of both sides gives: e^x = 2 → log(e^x) = log 2 → x log e = log 2 Dividing both sides by log e gives: x = (log 2)/(log e) The value of the logarithm of the base when taken to that base is 1. The logarithms can be taken to any base you like, however, if the base is e (natural logs, written as ln), then ln e = 1 which gives x = (ln 2)/1 = ln 2 This is in fact the definition of a logarithm: the logarithm to a specific base of a number is the power of the base which equals that number. In this case ln 2 is the number x such that e^x = 2. ---------------------------------------------------- This also means that you can calculate logs to any base if you can find logs to a specific base: log (b^x) = y → x log b = log y → x = (log y)/(log b) In other words, the log of a number to a given base, is the log of that number using any [second] base you like divided by the log of the base to the same [second] base. eg log₂ 8 = ln 8 / ln 2 = 2.7094... / 0.6931... = 3 since log₂ 8 = 3 it means 2³ = 8 (which is true).
