One to one.
As I understand it, the number of factor pairs is equal to the number of rectangles.
The number of square tiles is always equal to factor pairs. As an example, imagine a rectangle that contains 8 squares - 2 rows of 4. 2 X 4 = 8. In other words, the dimensions of the rectangles are ALWAYS equal to a factor pair of the number of squares in the rectangle. A rectangle containing 24 squares could be made as 24x1, 12x2, 8x3, or 6x4.
50
Here's something to think about: -- Every rectangle is a parallelogram. There are an infinite number of them. -- There are also an infinite number of more parallelograms that are not rectangles.
This is because 36 is a composite number.A prime number, p, has only the factorisation 1*p and so that is the only rectangle possible. But for a composite number there is at least one other factor q which may have a factor pair q' such that q*q' = p. q and q' could be the same if the number p was the square of q.So then you have rectangles of size 1*p and q*q'.
Number of factor pairs = number of rectangles
As I understand it, the number of factor pairs is equal to the number of rectangles.
The number of square tiles is always equal to factor pairs. As an example, imagine a rectangle that contains 8 squares - 2 rows of 4. 2 X 4 = 8. In other words, the dimensions of the rectangles are ALWAYS equal to a factor pair of the number of squares in the rectangle. A rectangle containing 24 squares could be made as 24x1, 12x2, 8x3, or 6x4.
The number of square tiles is always equal to factor pairs. As an example, imagine a rectangle that contains 8 squares - 2 rows of 4. 2 X 4 = 8. In other words, the dimensions of the rectangles are ALWAYS equal to a factor pair of the number of squares in the rectangle. A rectangle containing 24 squares could be made as 24x1, 12x2, 8x3, or 6x4.
You could make 5 rectangles with 10 squares
The number one.
There are an infinite number of rectangles for any given area, while there is only one square for any given area. The number of integer-value rectangles depends on the area and the number of integer factors of a whole-number area. Example: a rectangular area of 6 square inches could be enclosed by rectangles that were 1x6, 2x3, 3x2, and 6x1. Non-integer dimensions would include 1.5x4 and 1.2x5 inches.
yes i think it could
50
Here's something to think about: -- Every rectangle is a parallelogram. There are an infinite number of them. -- There are also an infinite number of more parallelograms that are not rectangles.
This is because 36 is a composite number.A prime number, p, has only the factorisation 1*p and so that is the only rectangle possible. But for a composite number there is at least one other factor q which may have a factor pair q' such that q*q' = p. q and q' could be the same if the number p was the square of q.So then you have rectangles of size 1*p and q*q'.
The only number that could be both a factor and a multiple is 7 itself.