The discriminant
Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.
It's much faster in most cases; however, factoring is not always possible.
You'll typically use it when solving a quadratic equation - when factoring isn't obvious.
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
A quadratic equation.
The discriminant
Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.Yes and they do in factoring quadratic equations.
By knowing how to use the quadratic equation formula.
It's much faster in most cases; however, factoring is not always possible.
You'll typically use it when solving a quadratic equation - when factoring isn't obvious.
The quadratic formula is used all the time to solve quadratic equations, often when the factors are fractions or decimals but sometimes as the first choice of solving method. The quadratic formula is sometimes faster than completing the square or any other factoring methods. Quadratic formula find: -x-intercept -where the parabola cross the x-axis -roots -solutions
One would use the quadratic formula for solving binomials that are otherwise hard to factor. You can find both real and imaginary solutions using this method, making it highly superior to factoring in this regard.
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
1
If you are in the mathematics field then you might be using it everyday; otherwise... not so much
Yes, however not all quadratic equations can easily be solved by factoring, sometimes you can factor and sometimes it is easier to use the quadratic formula. Example: x2 + 4x + 4 This can be easily factored to (x + 2)(x +2) Therefore the answer is -2 by setting x +2 = 0 and solving for x This can be done using the quadratic equation and you would get the same results, however, it was much faster to factor instead.