4+24=x
28=x
The sum of one number must be itself, so the answer is 2.4
24+16=40
Write a pair of number which have a sum of 11 and a product of 24?
7
Let the number be x: 5x+x = 24 6x = 24 x = 4
Suppose one of the numbers is x. Then, because they sum to 82, the other number is 82 - x. Then their difference gives the equation x - (82 - x) = 24 or 2x - 82 = 24
the sum of 18 and a number equals 24
The sum of one number must be itself, so the answer is 2.4
24+16=40
Let's denote the two numbers as x and y. We know that xy = 80 and x + y = 24. We can solve this system of equations by substituting one equation into the other. By substituting y = 24 - x into the first equation, we get x(24 - x) = 80. Simplifying this equation gives us a quadratic equation: x^2 - 24x + 80 = 0. Solving this quadratic equation will give us the values of x and y.
Write a pair of number which have a sum of 11 and a product of 24?
24(x + 2.25)
7
Start by setting up an equation. Use x for the integer. The equation would be: x/-3=12+-20 Find the sum of 12 and -20 which is -8. Therefore the equation would now be: x/-3=-8 Multiply -8 by -3 which equals 24. Therefore x=24 Plug it back into the equation to check that it works: 24/-3=12+-20 24/-3=-8 -8=-8 Thefore 24 is the integer that when divided by -3 it equals the sum of 12 and -20.
The term "sum" implies the answer to addition.Example: What is the sum of 10 and 14?10 + 14 = 24
Let the number be x: 5x+x = 24 6x = 24 x = 4
That would be 24 and 61, sum: 24+61=85 and 61-24=37