if it is 2x-3=19 then you add 3 to both sides and divide by 2
but if it is 2(x-3) then you distribute 2 into x and 3: 2x-6=19 then add 6 to both sides and dividing by 2
One equation with two unknowns usually does not have a solution.
Since that isn't an equation, there is really nothing to solve.
IMPOSSIBLE
No.
It is x = -5
y2=x3+3x2
One equation with two unknowns usually does not have a solution.
(a) y = -3x + 1
2+4 (which equals 6) x3 (equals 18) +1 = 19
Since that isn't an equation, there is really nothing to solve.
IMPOSSIBLE
x^3=2x+5 x^3-2x-5=0 Graph the equation or use a calculator. x= 2.09455148
No.
It is x = -5
No, it is not.
(xn+2-1)/(x2-1)
no only equations with x2 and lower powers can be considered quadratic. those with x3 cannot be considered quadratic, just as x2 cannot be considered linear