It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.
It depends on how many other positions are on the spinner. The question, as asked, cannot be answered. Please restate the question, giving also the total number of positions on the spinner.
Design it so that is has 4n sides where n is an integer and then make sure that 3n of these are blue. So, if n = 1, then 3 out of 4 are blue or n = 2, and 6 out of 8 are blue or n = 3, and 9 out of 12 are blue and so on.
Presuming that the spinner and the number cube are both "fair", then no - spinning the spinner and tossing the six-sided number cube are called statistically independent events. They do not influence each other, and it does not matter which order the events occur in.
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
4
it will land on red once and it will land on blue once aswell
The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.
That would depend on how many numbers are on the spinner and the cube. The more numbers there are, the less likely it is that they would both land an any given number.
The answer depends on the shape of the spinner and the numbers on it.
18
There are 10 possibilities. For every space on the spinner you land on, there are two other outcomes (heads and tails). Say the colors are Blue, Green, Yellow, Red, and Purple. Here would be the final outcomes. Blue - heads or tails Green - heads or tails Yellow - heads or tails Red - heads or tails Purple - heads or tails
To calculate the probability of spinning the black region twice on a spinner, you first need to determine the total number of possible outcomes when spinning the spinner twice. Let's say the spinner has 8 equal sections, with 2 black regions. The total outcomes for spinning the spinner twice would be 8 x 8 = 64. The probability of landing on the black region twice would be 2/8 x 2/8 = 4/64 = 1/16. Therefore, the probability of landing on the black region twice is 1/16 or approximately 0.0625.
It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.
It depends on how many other positions are on the spinner. The question, as asked, cannot be answered. Please restate the question, giving also the total number of positions on the spinner.
The answer depends on the number of sides on the spinner and how they are numbered.
It's the water, and the green is land.