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4 of 4
It is possible!
It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.
It depends on how many other positions are on the spinner. The question, as asked, cannot be answered. Please restate the question, giving also the total number of positions on the spinner.
The probability of getting a 6 with a single standard die is 1/6; so if a die is thrown 54 times the expectation (in the long run) would be that 1/6 of them would show a 6: 1/6 × 54 = 9 times. You would expect a 6 on about 9 occasions.
The answer depends on the number of sides on the spinner and how they are numbered.
You can expect the spinner to land an odd number 25 times out of 50.
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The answer will depend on how man divisions the spinner has and how many of them are labelled A. Since you have chosen not to share this information the question cannot be answered.
The answer will depend on how man divisions the spinner has and how many of them are labelled c. Since you have chosen not to share this information the question cannot be answered.
The answer depends on the shape of the spinner and the number of colours on it. And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
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It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...
A fair coin would be expected to land on heads 10 times on average.
I would expect it to land on a number of 4 or higher 50% of the time or roughly 24 times.
The probability that the spinner will land on six depends on how many numbers are on the spinner. If the spinner is only 1 through 6, then there is a 16.67% probability that the spinner will land on six with each spin.