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To calculate the number of 12-number combinations using numbers 1-36, we can use the formula for combinations: nCr = n! / r!(n-r)!, where n is the total number of items to choose from (36) and r is the number of items to choose (12). Plugging in the values, we get 36C12 = 36! / 12!(36-12)! = 36! / 12!24! = (363534*...25) / (121110...*1). This simplifies to 125,736,770 unique combinations.
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What are the 5-number combinations not using any number twice?
There are infinitely many numbers and so infinitely many possible combinations.
How many combinations of 5 are there in 0 to 10 numbers?
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
How many 4-number combinations using numbers 0-9?
9000
How many 3 number combinations can you make using the numbers 1-45?
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
How many combinations using 8 numbers are there in 20 numbers what are these combinations?
There are 125970 combinations and I am not stupid enough to try and list them!
