Study guides

☆☆

Q: How many 3 digit combinations are there in the numbers 1 to 9?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

There are 1140 five digit combinations between numbers 1 and 20.

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

7

There are 840 4-digit combinations without repeating any digit in the combinations.

There are 167960 9 digits combinations between numbers 1 and 20.

Related questions

There are 1140 five digit combinations between numbers 1 and 20.

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

7

There are 840 4-digit combinations without repeating any digit in the combinations.

There are 167960 9 digits combinations between numbers 1 and 20.

There are 167960 9 digits combinations between the numbers 1 and 20.

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.

There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.

-8

It is: 9C7 = 36

15

6 ways: 931,913,139,193,391,319

People also asked