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A room that is 25.5 yards * 32 yards has a perimeter of 2*(25.5 + 32) = 2*57.5 = 115 yards. If each string of lights is 5 yards long, the number of strings required is 115/5 = 23.
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2 rhombuses and 2 triangles
4
Yes First construct an equilateral triangle: Draw the base side of the triangle and label the ends A and B - this will be the first side of the hexagon. Set the compass to the length of the side. With the compass on one end of the line (point A), draw an arc to one side of the line (roughly near the middle). With the compass on the other end of the line (point B), draw a second arc to intersect the first arc (call this point O) - this is the apex of the triangle. Normally when constructing the triangle side OA and OB would be drawn in, however as a hexagon is being constructed only the location of O is needed. This point O will be the centre of the hexagon. Now construct 4 further equilateral triangles: For the first use OB as the base (the actual line is not needed, just its endpoints), construct its apex C and using the straight edge join B to C. For the next, use OC as the base, construct its apex D and join C to D Then use OD, construct apex E and join D to E Finally using OE, construct apex F and join E to F. The hexagon can now be completed by joining F to A.
A room that is 25.5 yards * 32 yards has a perimeter of 2*(25.5 + 32) = 2*57.5 = 115 yards. If each string of lights is 5 yards long, the number of strings required is 115/5 = 23.
Two strings are needed to string a tennis racket. The length of the string is to be about 11 to 12 meters.
The strings are paired in courses, but they only have four or five courses of strings rather than six. They are called stanford strings.
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6
4 sqaure
dipped lights? What is dipped lights?
2 rhombuses and 2 triangles
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12 of then but if they are joined together in the form of a 6 sided hexagon then 6 endpoints are needed.
That depends how many sections you wish to divide it into.
Head lights, port, starboard and stern lights (on 28' pontoon boat).