If you allow 'zero' as an even digit, then . . .
-- The first digit can be any one of 4 (2, 4, 6, or 8).
For each of these . . .
-- The second digit can be any one of 4 (zero and the 3 remaining from the first group).
-- Total number of possibilities = 4 x 4 = 16.
If you don't accept 'zero' as an even digit, then . . .
-- The first digit can be any one of 4 (2, 4, 6, or 8).
For each of these . . .
-- The second digit can be any one of the remaining 3.
-- Total number of possibilities = 4 x 3 = 12.
There are 238 - 1 = 237 numbers between 1 and 238. To find the number of digits, we need to consider the range of numbers from 1 to 9 (1-digit numbers), 10 to 99 (2-digit numbers), and 100 to 238 (3-digit numbers). There are 9 one-digit numbers, 90 two-digit numbers, and 139 three-digit numbers between 1 and 238, totaling 9 + 90 + 139 = 238 digits.
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
73 is the largest two-digit number that is prime and has prime numbers for both of its digits.
This cannot be answered. This will have to be written to where it can be understood.
There are 999 numbers between 1 and 1000, which includes all the integers from 1 to 999. If you're asking about the count of individual digits used in writing these numbers, they collectively comprise a total of 2887 digits. This is calculated by considering the number of digits in one-digit (1-9), two-digit (10-99), and three-digit numbers (100-999).
Since both of those numbers contains four digits, there are no three-digit numbers between them.
There are 238 - 1 = 237 numbers between 1 and 238. To find the number of digits, we need to consider the range of numbers from 1 to 9 (1-digit numbers), 10 to 99 (2-digit numbers), and 100 to 238 (3-digit numbers). There are 9 one-digit numbers, 90 two-digit numbers, and 139 three-digit numbers between 1 and 238, totaling 9 + 90 + 139 = 238 digits.
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
73 is the largest two-digit number that is prime and has prime numbers for both of its digits.
This cannot be answered. This will have to be written to where it can be understood.
There are 999 numbers between 1 and 1000, which includes all the integers from 1 to 999. If you're asking about the count of individual digits used in writing these numbers, they collectively comprise a total of 2887 digits. This is calculated by considering the number of digits in one-digit (1-9), two-digit (10-99), and three-digit numbers (100-999).
In the numbers 1-9 each number has 1 digit and there are 9 of them, so that's 9.In 10-99 each number has 2 digits, and there are 90 of them: 2x90 = 180There are 900 three digit numbers [100 through 999]: 2700 digits.There are 9000 four digit numbers: 36000 digits.90,000 numbers with five digits: 450,000 digits.900,000 numbers with six digits: 5,400,000 digits.Then 1 number with seven digits: 7 digits.Add them up and you have 5,888,896 digits.
Any number that has 4 or 5 digits. A digit in a number is one number place. 1 has 1 digit, 11 has 2 digits, 111 has 3 digits, and so on.
73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.
2
The greatest 5 digit number is 98765. The greatest 5 digit number that doesn't contain any of those digits is 43210. The difference between them is 55555.The two five digit numbers using all ten digits once and only once between them that sum to the largest value are 97531 and 86420. They sum to 183,951 and have a difference of 11111. These two numbers are not unique ... you can switch any pair of digits between the two numbers as long as you keep them in the same position without changing the sum, though this will change the difference.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.