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What are the possible biggest 4 digit numbers with 4 different digit?
5
How many 4 digit numbers contain the digit 5?
There are 9000 4-digit numbers. 8*9*9*9 = 5832 of them do not contain a 5 The remaining 3168 contain a 5.
How many 5 digit numbers are there in total?
4
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many 4 digit numbers begin with 5?
1000
What are the possible biggest 4 digit numbers with 4 different digit?
5
How many 4 digit numbers can be formed from the digits 12345?
The first digit can have 5 possible numbers, the second digit can have 4, the third 3, the fourth 2. 5
How many 4 digit numbers contain the digit 5?
There are 9000 4-digit numbers. 8*9*9*9 = 5832 of them do not contain a 5 The remaining 3168 contain a 5.
How many 5 digit numbers are there in total?
4
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
What are 4 digit numbers that are multiples of 5?
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P
What are 5 digit numbers that are divisible by 4?
40,000, 80,000
How many 4 digit numbers begin with 5?
1000
How many 4 digit numbers do not begin with 5?
8000
How many 4 digit numbers have only odd numbers?
To find the number of 4-digit numbers with only odd digits, we need to consider the options for each digit. Since odd digits are 1, 3, 5, 7, and 9, there are 5 choices for each digit. Therefore, the total number of 4-digit numbers with only odd digits is calculated as 5 x 5 x 5 x 5 = 625. So, there are 625 4-digit numbers that have only odd numbers.
How many 3 digit numbers can be made using the digits 3 4 5 and 6 if the digits can repeated?
There are 4 options for the hundreds digit (3, 4, 5, or 6), and 4 options for the tens digit (including the possibility of repeating the hundreds digit). Similarly, there are 4 options for the units digit. Therefore, the total number of 3-digit numbers that can be formed using the digits 3, 4, 5, and 6 with repetition allowed is 4 x 4 x 4 = 64.
How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?
5*5*4*4 = 400
