There are four 3s in 12. This can be determined by dividing 12 by 3, which equals 4. Each division represents one occurrence of the number 3 within 12.
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
12 1/3s is 12/312/3 = 4
4
16
4 3s = 4*3 = 12, which is a rational number.
12
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
To solve the equation 2s + s + 12 = 132, you first combine like terms on the left side. This gives you 3s + 12 = 132. Next, you isolate the variable by subtracting 12 from both sides to get 3s = 120. Finally, you divide by 3 on both sides to find that s = 40.
2s + s + 12 =132 ie 3s = 132 -12 3s = 120 s = 40
28 3s
12 1/3s is 12/312/3 = 4
its clearly 8 3 6 9 12 15 18 21 4
How many 3s are in 15
It is 1.08333... (with the 3s repeating).
9
4