Without repetition, 300. Of these 48 will have a 2 in the units place.
-5
It depends on which place value is given!
Total possible 4-digit numbers= 1000, 1001,...,9999 = 9000 Total with same digit numbers = 1111,2222,...,9999 = 9 9000 - 9 = 8991
3897
256 Each "place holder" if you will, may contain 4 numbers. So it is 4x4x4x4
-5
It depends on which place value is given!
Total possible 4-digit numbers= 1000, 1001,...,9999 = 9000 Total with same digit numbers = 1111,2222,...,9999 = 9 9000 - 9 = 8991
3897
256 Each "place holder" if you will, may contain 4 numbers. So it is 4x4x4x4
To multiply two digit numbers, multiply each place value of a factor by each place value digit and add the results.
Numbers that contain the digit 5 include any integer or decimal that has a '5' in any place value, such as 5, 15, 25, 50, 105, or 5.7. This also extends to negative numbers, like -5 or -15. Essentially, any number that can be expressed in numerical form and has '5' in its digits qualifies.
The numbers between 4,000 and 10,000 _ _ _ _ 1st place only can filled by 4, 5, and 6 2nd place only can filled by the other 4 digit 3rd place only can filled by the other 3 digit 4th place only can filled by the other 2 digit So: 3 x 4 x 3 x 2 = 72 numbers The numbers greater than 10,000 5 x 4 x 3 x 2 x 1 = 120 numbers The total is 72 + 120 = 192 numbers can formed.
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
There is no difference. In both cases, the place value, of any digit, is ten times the place value of the digit to its right.
199998
Greatest: 989949 Least: 100000