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105 115 125 135 145 155 165 175 185 195 205 215 225 235 245 255 265 275 285 295 305 315 325 335 345 355 365 375 385 395 405 415 425 435 455 465 475 485 495 +100(all of 500+) = 139 i guess.

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Q: How many 3 digit numbers with the number 5 in it?
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How many 3-digit numbers are there using 2 4 6 8 and 9?

There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125


How many sets of 3-digit numbers can be made using 7 numbers and no duplicates within the 3-digit number?

210


How many 3 digit number are divisible by 5?

There are 180 3-digit numbers divisible by five.


How many 3 digit numbers can be found using 3 of the digits 6789 only once in each number?

4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.


How many 3-digit number are multiples of 18?

There are 49 3-digit numbers - from 108 to 990 inclusive.


How do 3 digit numbers compare to 4 digit numbers?

3 digit numbers are lessthan 4 digit numbers


How many 3 digit numbers are there show rough work?

The largest 3-digit number=999 the smallest 3-digit number=100 total number of 3 digit number=(999-100)+1 =899+1=900


What are the products of multiplying 2 digit numbers by 2 digit numbers?

A 3 or 4 digit number.


How many 3-d How many 3-digit numbers will be there which are divisible by 19igit numbers with atleast one 5 in their digits?

None. 3 digit numbers are not divisible by 19 digit numbers.


Carlin wrote a 447 page book on the history of mathematics. She numbered the pages by hand beginning with page 1. How many total digits did she write when numbering the pages?

Answer1 x 9 (number of 1 digit numbers) plus 2 x 89 (number of 2 digit numbers) plus 3(number of 3 digit numbers) x 347 = 1228 The correct answer is 1323. Here is how you do it.1 digit numbers = 92 digit numbers = 90 (99-9) number of 2 digit numbers - number of 1 digit numbers3 digit numbers = 378 (477-99) number of 3 digit numbers - number of 1 & 2 digit numbersSo, the solution is:1x9 = 92x90 = 1803x378 = 11349+180+378 = 1323


How many 3 digit numbers can be formed from 3769 if each digit is used only once?

Choose from 4 for the first number, 3 for the second number, and 2 for the third number. Therefore there are 4*3*2 = 24 three digit numbers can be formed from 3769 if each digit is used only once.


How many numbers has a 3 digit and that's a factor with the number 6 and 7?

21 of them.