105 115 125 135 145 155 165 175 185 195 205 215 225 235 245 255 265 275 285 295 305 315 325 335 345 355 365 375 385 395 405 415 425 435 455 465 475 485 495 +100(all of 500+) = 139 i guess.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
210
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
3 digit numbers are lessthan 4 digit numbers
The largest 3-digit number=999 the smallest 3-digit number=100 total number of 3 digit number=(999-100)+1 =899+1=900
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
210
There are 180 3-digit numbers divisible by five.
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
There are 49 3-digit numbers - from 108 to 990 inclusive.
3 digit numbers are lessthan 4 digit numbers
The largest 3-digit number=999 the smallest 3-digit number=100 total number of 3 digit number=(999-100)+1 =899+1=900
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
A 3 or 4 digit number.
None. 3 digit numbers are not divisible by 19 digit numbers.
Answer1 x 9 (number of 1 digit numbers) plus 2 x 89 (number of 2 digit numbers) plus 3(number of 3 digit numbers) x 347 = 1228 The correct answer is 1323. Here is how you do it.1 digit numbers = 92 digit numbers = 90 (99-9) number of 2 digit numbers - number of 1 digit numbers3 digit numbers = 378 (477-99) number of 3 digit numbers - number of 1 & 2 digit numbersSo, the solution is:1x9 = 92x90 = 1803x378 = 11349+180+378 = 1323
Choose from 4 for the first number, 3 for the second number, and 2 for the third number. Therefore there are 4*3*2 = 24 three digit numbers can be formed from 3769 if each digit is used only once.