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Related Questions

How many 3 digit numbers can be formed from the digits 1234?

64 if repetition is allowed.24 if repetition is not allowed.


How many 4 digit numbers can be made to give the sum of 6?

If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.


How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.


How many three digit numbers can be formed using the digits 873 and 6 without repetition?

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24


How many numbers can be formed using the digits 37 and 9 without repetition?

15 of them.


How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?

125


How many 2-digit numbers can be produce using the digits 123456789 if repetition is not allowed?

-123456787


How many 3-digits number can you make from the digits 1 2 and 3?

33 = 27 with repetition, 3! = 3*2*1 = 6 without repetition.


How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?

290


How many number combinations can you make with the numbers 1234567890?

The number of combinations you can make with the digits 1234567890 depends on how many digits you want to use and whether repetition is allowed. If you use all 10 digits without repetition, there are 10! (10 factorial) combinations, which equals 3,628,800. If you are choosing a specific number of digits (for example, 3), the number of combinations would be calculated using permutations or combinations based on the rules you set.


How many 3 digit number can be made using the digits 2 4 7 9?

24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.


Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?

There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.