252 combinations, :)
12,108,327
The number of combinations is 32!/[6!*(32-6)!] where n! represents 1*2*3*...*n The answer is 32*31*30*29*28*27/(6*5*4*3*2*1) = 906192
To calculate the number of 3-digit combinations using numbers 1-6, including 1 and 6, we need to consider the total number of options for each digit. Since we are including 1 and 6, there are 6 options for the hundreds place (1-6), 6 options for the tens place (1-6), and 6 options for the ones place (1-6). Therefore, the total number of 3-digit combinations is 6 x 6 x 6 = 216.
7
252 combinations, :)
There are 6C3 = 20 such combinations.
The number of combinations of 6 letters is 6! or 720.
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060
12,108,327
There are 8145060 combinations.
138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.
Any multiple of 138
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
654321-100000= 554321 combinations
There are 15 combinations.
6 of them.