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Q: How many 6 number combinations in 138?

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252 combinations, :)

12,108,327

The number of combinations is 32!/[6!*(32-6)!] where n! represents 1*2*3*...*n The answer is 32*31*30*29*28*27/(6*5*4*3*2*1) = 906192

Any 6 from 51 = 18,009,460 combinations

7

Related questions

252 combinations, :)

There are 6C3 = 20 such combinations.

The number of combinations of 6 letters is 6! or 720.

12,108,327

There are 8145060 combinations.

Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060

Any multiple of 138

138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.

55C6 = 28,989,675

It is: 55C6 = 28,989,675

55C6 = 28,989,675

6 of them.

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