There are 4845 combinations of 4 numbers from the set 1 - 20
nCr = n!/r!(n-r)!
⇒ 20C4 = 20!/4!(20-4)!
= 20 x 19 x 18 x 17/4 x 3 x 2 x 1
= 4845
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Only one, since the order of the numbers does not matter in a combination.
How many numbers are there are in each combination ?If one, then 4 combinations.If two, then 6 combinations.If three, then 4 combinations.If four, then only 1 combination.
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
262
There are 360 of them.
there are 63 combos
Only one, since the order of the numbers does not matter in a combination.
How many numbers are there are in each combination ?If one, then 4 combinations.If two, then 6 combinations.If three, then 4 combinations.If four, then only 1 combination.
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
Just one. unless you count 123456 different from 132456 then there are 46656 * * * * * But you cannot count 123456 as different from 132456 since it is NOT a different combination. And the question was about combinations.
Well, darling, if you want a 4-digit combination with no repeated numbers using 0-9, you simply multiply the number of choices for each digit. So, for the first digit, you have 10 options, then 9 for the second (can't repeat the first digit), 8 for the third, and 7 for the fourth. Multiply those together and you get 10 x 9 x 8 x 7 = 5040 unique combinations. Hope that tickles your fancy!
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
How many numbers per combination?
262
-- 4 numbers can be lined up in 24 different ways-- If the order doesn't matter, then there's only one4-number combination of 4 numbers.
12 different numbers.
There are 360 of them.