With each digit having only 2 possibilities, the answer is 2 to the 4th power, which is 16. The 4 is because there are 4 digits. Think about the binary numbers 0000 to 1111, there are 2 possibilities for each digit. If your constraint is that the digits must have at least one 2 and at least one 5, then eliminate the two combinations 2222 and 5555, and that answer would be 14.
The square root of -4 is not irrational, it is imaginary. Irrational numbers are numbers that cannot be expressed as a fraction, like the square root of 2. Irrational numbers, however, are a subset of real numbers. The square root of -4 however, is not even a real number because no real number, when squared, gives -4. Therefore the square root of -4 is an imaginary number.In calculus, the root is expressed as 2i where iis the square root of -1.
To find a square number, you have to times a number, for example 4 only once. So the square number will be 16 because you timed 4x4.
generally you would multiply a number by itself, but i have found out a marvelous trick, and it is pretty easy since I am only a child, but starting with 1, if you add three, you get four, the next square number. then you add five to get nine the next square number, then seven to get sixteen and so on. So in simpler terms you take one and add three to get the next square number, then add five, then seven counting by odd numbers. Here is an equation. the bold numbers are the square numbers and the Italic numbers are the progressing odd numbers.1+3= 4+5= 9+7=16and so on.
There are an infinite number of possible answers. 152*1 or 151+1 or 153-1 or 153/1 and then we can try with 2, 3, 4, etc and then with 0.1, 0.2 etc and then 1.1, 1.2, 1.3, ... 2.1, 2.2, 2.3, ... 3.1, etc and then irrational numbers.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
how many combinations of 4 numbers are there in 7 numbers
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
it is hard to say there are lot of combinations belive or not * * * * * If the previous answerer thinks 15 is a lot then true. There are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations. Not so hard to say!
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 15 combinations.
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
There are: 36C4 = 58,905
9000
4 of them. In a combination the order of the numbers does not matter.
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
9000