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Assuming you're allowed to repeat numbers, the answer is 81. For each digit, you have three choices: 2, 5, and 6. So there are three one-digit numbers you can make, and each one digit number can be combined with any of three other digits to make a two-digit number, giving 9 (3 times 3) possibilities. Now you can take any of the nine two-digit numbers as the tens and ones places in the four-digit number and any other two-digit number as the thousands and hundreds places, which gives 81 (9 times 9) possibilities.

If you can't repeat numbers, the answer is zero because you don't have enough numbers to fill all the digits.

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Q: How many 4 digit combinations can be made from these 3 numbers 2-6-5?
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