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Assuming you're allowed to repeat numbers, the answer is 81. For each digit, you have three choices: 2, 5, and 6. So there are three one-digit numbers you can make, and each one digit number can be combined with any of three other digits to make a two-digit number, giving 9 (3 times 3) possibilities. Now you can take any of the nine two-digit numbers as the tens and ones places in the four-digit number and any other two-digit number as the thousands and hundreds places, which gives 81 (9 times 9) possibilities.
If you can't repeat numbers, the answer is zero because you don't have enough numbers to fill all the digits.
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How many 4 digit combinations can be made from 10 numbers with out repeating?
The answer is 10C4 = 10!/[4!*6!] = 210
If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
How many combinations of three one digit numbers equal 4?
5
How many combinations of 2 digit numbers can be produced from 01 99?
45.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many 4 digit combinations can be made using numbers 1 2 3 4 6?
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
How many 7 digit combinations can be made using the numbers 1 through 9?
It is: 9C7 = 36
If using numbers 0 through 9 how many different 4 digit combinations can be made?
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
If using numbers 1 through 4 how many different 4 digit combinations can be made?
10,000
If using numbers 1 through 8 how many different 4 digit combinations can be made?
15
How many different combinations can be made of 9 digit social security numbers can be made?
10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).
How many 5 digit combinations are there from 1-20?
To find the number of 5-digit combinations from 1 to 20, we first calculate the total number of options for each digit position. Since the range is from 1 to 20, there are 20 options for the first digit, 20 options for the second digit, and so on. Therefore, the total number of 5-digit combinations is calculated by multiplying these options together: 20 x 20 x 20 x 20 x 20 = 3,200,000 combinations.
How many 4 digit combinations can be made from 10 numbers with out repeating?
The answer is 10C4 = 10!/[4!*6!] = 210
How many 4 digit combanations using the numbers 1-7?
There are 840 4-digit combinations without repeating any digit in the combinations.
How many 4 digit combinations can you get from numbers 1226?
You would get 4!/2! = 12 combinations.
