Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
-2
17
The number is 42.
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
-2
17
There are 45 such numbers.
72. (with the range of two digit numbers being from 10 to 99).
That refers to any number that is a multiple of 2. Such numbers can be easily recognized by the fact that their last digit is a multiple of 2, i.e., the last digit is one of (0, 2, 4, 6, 8).
The number is 42.
1
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
45
45 of them.