Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
-2
17
The number is 42.
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15
-2
How many two digit numbers are there in which the tens digit is greater than the oneβs digit ?
17
There are 45 such numbers.
72. (with the range of two digit numbers being from 10 to 99).
That refers to any number that is a multiple of 2. Such numbers can be easily recognized by the fact that their last digit is a multiple of 2, i.e., the last digit is one of (0, 2, 4, 6, 8).
The number is 42.
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.
1
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
Ten.