10999
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
There are 600 such numbers.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
You are not using the digit zero (0), so there are nine possible digits. If repetition is allowed and order is important (like a 4 digit combination lock), then the answer is 94 = 6561. If repetition is not allowed and order is important, then you have 9! / (9-4)! = 9*8*7*6*5 = 3024.
-123456787
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
290
20 of them, if repetition is not allowed.
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
There are 600 such numbers.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
30 without repetition (6P2) 66 with repetition (12C2)
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
You are not using the digit zero (0), so there are nine possible digits. If repetition is allowed and order is important (like a 4 digit combination lock), then the answer is 94 = 6561. If repetition is not allowed and order is important, then you have 9! / (9-4)! = 9*8*7*6*5 = 3024.
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.