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How many 4 digit numbers can you make using numbers 0 through 9 With repetition?
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∙ 15y ago
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Wiki User
∙ 15y ago
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How man 7 digit combinations can be made using numbers 0 through 9?
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
How many five digit multiples of 3 are formed using 012346 and 7 without repetition?
There are 600 such numbers.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
If using numbers 1 through 9 how many 4 digit combinations can be made?
You are not using the digit zero (0), so there are nine possible digits. If repetition is allowed and order is important (like a 4 digit combination lock), then the answer is 94 = 6561. If repetition is not allowed and order is important, then you have 9! / (9-4)! = 9*8*7*6*5 = 3024.
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many 2-digit numbers can be produce using the digits 123456789 if repetition is not allowed?
-123456787
How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?
290
How man 7 digit combinations can be made using numbers 0 through 9?
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
How many two digit numbers can be made using the numbers 1 2 4 5 and 7?
20 of them, if repetition is not allowed.
How many 3 digit number can be made using the digits 2 4 7 9?
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
How many five digit multiples of 3 are formed using 012346 and 7 without repetition?
There are 600 such numbers.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?
30 without repetition (6P2) 66 with repetition (12C2)
If using numbers 1 through 9 how many 4 digit combinations can be made?
You are not using the digit zero (0), so there are nine possible digits. If repetition is allowed and order is important (like a 4 digit combination lock), then the answer is 94 = 6561. If repetition is not allowed and order is important, then you have 9! / (9-4)! = 9*8*7*6*5 = 3024.
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?
9*8*7 = 504 of them.
