answersLogoWhite

0


Best Answer

10999

User Avatar

Wiki User

โˆ™ 2008-11-06 03:50:49
This answer is:
User Avatar
Study guides

Algebra

20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

โžก๏ธ
See all cards
3.8
โ˜†โ˜…โ˜†โ˜…โ˜†โ˜…โ˜†โ˜…โ˜†โ˜…
2018 Reviews

Add your answer:

Earn +20 pts
Q: How many 4 digit numbers can you make using numbers 0 through 9 With repetition?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many 2-digit numbers can be produce using the digits 123456789 if repetition is not allowed?

-123456787


How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?

290


How many two digit numbers can be made using the numbers 1 2 4 5 and 7?

20 of them, if repetition is not allowed.


How man 7 digit combinations can be made using numbers 0 through 9?

10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.


How many 3 digit number can be made using the digits 2 4 7 9?

24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.


How many five digit multiples of 3 are formed using 012346 and 7 without repetition?

There are 600 such numbers.


How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?

30 without repetition (6P2) 66 with repetition (12C2)


How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.


How many three digit numbers can be formed using the digits 873 and 6 without repetition?

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24


If using numbers 1 through 9 how many 4 digit combinations can be made?

You are not using the digit zero (0), so there are nine possible digits. If repetition is allowed and order is important (like a 4 digit combination lock), then the answer is 94 = 6561. If repetition is not allowed and order is important, then you have 9! / (9-4)! = 9*8*7*6*5 = 3024.


What is the sum of all the four digit numbers formed using the digits 0 1 2 and 3 if repetition is allowed?

It is 415968.


How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?

9*8*7 = 504 of them.

People also asked