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How many 4 digit numbers can be formed by the digits 1 2 3 4 using each digit only once?
24 different numbers.
What is the largest 6 digit number using only even numbers using each number only once?
998,000
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
How is multiplying by multi-digit numbers similar to multiplying by two-digit numbers?
Multiplying by multi-digit numbers is similar to multiplying by two-digit numbers in that both processes involve breaking down the numbers into place values and multiplying each digit by each digit in the other number. The key similarity lies in the application of the distributive property, where each digit in one number is multiplied by each digit in the other number, and then the products are added together to get the final result. This process is consistent whether you are multiplying by a two-digit number or a multi-digit number.
How many 10 digit numbers can be formed using each digit once?
ten factorial = 10! = 3,628,800
How many three digit numbers containing 3 7 and 9 using each digit once?
six
How many 4 digit numbers can be formed by the digits 1 2 3 4 using each digit only once?
24 different numbers.
How many different numbers can you make with the digits 1 2 3 and 4 using each digit only once?
If you want 4-digit numbers, there are 24 of them.
What is the largest 6 digit number using only even numbers using each number only once?
998,000
What are all the possible 5 digit codes using the numbers 0-9?
There are 10000 such codes. Each of the numbers 0-9 can be in the first position. With each such first digit, each of the numbers 0-9 can be in the second position. With each such pair of the first two digits, each of the numbers 0-9 can be in the third position. etc.
How many 3-digit numbers are there using 2 4 6 8 and 9?
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
How is multiplying by multi-digit numbers similar to multiplying by two-digit numbers?
Multiplying by multi-digit numbers is similar to multiplying by two-digit numbers in that both processes involve breaking down the numbers into place values and multiplying each digit by each digit in the other number. The key similarity lies in the application of the distributive property, where each digit in one number is multiplied by each digit in the other number, and then the products are added together to get the final result. This process is consistent whether you are multiplying by a two-digit number or a multi-digit number.
How many five digit numbers can be formed using the numbers 1-60 only using each number once in each combination?
61
How do you multiply by two-digit numbers?
To multiply two digit numbers, multiply each place value of a factor by each place value digit and add the results.
How many 4 digit numbers can be created using 5 6 7 and 8 using each digit only 1 time in a number?
24 = 4*3*2*1 of them
