With 123 digits you can make 123 one-digit numbers.
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
24
There are no three didgit numbers but there are 63 three digit numbers.
24 = 4*3*2*1
With 123 digits you can make 123 one-digit numbers.
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
12,13,14 21,23,24 31,32,34 43,42,41 12 two-digit numbers
There are no three didgit numbers but there are 63 three digit numbers.
1
If you want 4-digit numbers, there are 24 of them.
9
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
52C6=(52!)/(6!*(52-6)!)=20,358,520
8 of them.
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.