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You have given us four digits. To rearrange them in all possible different ways: There are 4 choices for Digit-1, and for each of those ... there are 3 choices for Digit-2, and for each of those ... there are 2 choices for Digit-3, and for each of those ... there is only 1 choice left for Digit-4. So the total number of choices is: ( 4 x 3 x 2 x 1 ) = 24 BUT ... You can't tell the difference between the two '9's, so for every arrangement, there's another one that looks exactly like it, and you'd swear it's the same number. So the number of unique arrangements is only half of 24 = 12
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How many 1 digit numbers can make with 123 digits?
With 123 digits you can make 123 one-digit numbers.
How many two digit whole numbers are increased by 18 when their digits are reversed?
7 two-digit numbers.
How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
How many 3-d How many 3-digit numbers will be there which are divisible by 19igit numbers with atleast one 5 in their digits?
None. 3 digit numbers are not divisible by 19 digit numbers.
How many 5 digit numbers can be formed from the digits 012 if any of the digits can be repeated?
500
