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You have given us four digits. To rearrange them in all possible different ways: There are 4 choices for Digit-1, and for each of those ... there are 3 choices for Digit-2, and for each of those ... there are 2 choices for Digit-3, and for each of those ... there is only 1 choice left for Digit-4. So the total number of choices is: ( 4 x 3 x 2 x 1 ) = 24 BUT ... You can't tell the difference between the two '9's, so for every arrangement, there's another one that looks exactly like it, and you'd swear it's the same number. So the number of unique arrangements is only half of 24 = 12

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Q: How many 4 digit numbers have the same digits as 1989?
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