I believe the factors/digits would have to be either 1, 1, 2, 3 (12 combinations) or 1, 1, 1, 6 (4 combinations).
The product of a 4-digit multiplicand and a 1-digit multiplier can have either 4 or 5 digits. If the 4-digit number is multiplied by a multiplier of 1 to 9, the product will typically have 4 digits. However, if the multiplicand is multiplied by 10 (the maximum value for a 1-digit number), the product can reach a maximum of 5 digits. Thus, the product can range from 4 to 5 digits, depending on the specific numbers involved.
With 123 digits you can make 123 one-digit numbers.
7 two-digit numbers.
To form a two-digit number using the digits 0-9 without repetition, the first digit (the tens place) can be any digit from 1 to 9 (9 options), since a two-digit number cannot start with 0. The second digit (the units place) can then be any of the remaining 9 digits (including 0 but excluding the first digit). Therefore, the total number of two-digit numbers that can be formed is 9 (choices for the first digit) multiplied by 9 (choices for the second digit), resulting in 81 possible two-digit numbers.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
The product of a 4-digit multiplicand and a 1-digit multiplier can have either 4 or 5 digits. If the 4-digit number is multiplied by a multiplier of 1 to 9, the product will typically have 4 digits. However, if the multiplicand is multiplied by 10 (the maximum value for a 1-digit number), the product can reach a maximum of 5 digits. Thus, the product can range from 4 to 5 digits, depending on the specific numbers involved.
With 123 digits you can make 123 one-digit numbers.
There are 5460 five digit numbers with a digit sum of 22.
27 three digit numbers from the digits 3, 5, 7 including repetitions.
All of them.
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
757
There are 90000 5-digit numbers.
7 two-digit numbers.
To form a two-digit number using the digits 0-9 without repetition, the first digit (the tens place) can be any digit from 1 to 9 (9 options), since a two-digit number cannot start with 0. The second digit (the units place) can then be any of the remaining 9 digits (including 0 but excluding the first digit). Therefore, the total number of two-digit numbers that can be formed is 9 (choices for the first digit) multiplied by 9 (choices for the second digit), resulting in 81 possible two-digit numbers.
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
None. 3 digit numbers are not divisible by 19 digit numbers.