The easy answer is 0000 thru 9999, which is 10,000 combinations. A way to calculate this is by Nx
where N is the number of digits possible (here, 10 different digits are
possible) 0 through 9, and x is the number of places available (here we have 4 places available for a 4 digit number)
note the formula is N raised to the x power
meaning, 104
or 10 X 10 X 10 X 10 = 10,000 combinations
Another exampleHow many combinations are available using digits 0-3 for a 2 digit number?The possibilities are: 00 01 02 03 10 11 12 13 20 21 22 23 30
31 32 33
or 16 possibilities
the formula would tells us:
Nx is 42 or 4 x 4 = 16
* * * * *
THE ABOVE ANSWER IS WRONG!
Interesting but completely wrong since the answer confuses permutations and combinations. The combination 12 is the same as the combination 21.
The number of 4 digit combinations from the numbers 0 to 9 is 10C4 = 10!/[4!*6!]
=10*9*8*7/(4*3*2*1) = 210.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
9000
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
There are 10,000 four number combinations in the numbers 0 through 9. * * * * * No, that is simply not true. The combination 1234 is the same as the combination 2134 and 2314 and 1423 etc. So, there are just 8*7*6*5/(4*3*2*1) = 70 combinations.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
There are 45 combinations.
9000
9999
10P4 = 5040
The number of combinations of 7 numbers from 10 is 10C7 = 10*9*8/(3*2*1) = 120
Since there are only 3 digits available, repetition must be allowed. In that case, there are 30 combinations.
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
9
There are 10,000 four number combinations in the numbers 0 through 9. * * * * * No, that is simply not true. The combination 1234 is the same as the combination 2134 and 2314 and 1423 etc. So, there are just 8*7*6*5/(4*3*2*1) = 70 combinations.
7