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How many different three digit number combinations can be made with 0-9 with no repeat numbers when order of the number does not matter?
9
What else can I help you with?
How many different combinations of 5 numbers 5 number combination?
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
How many 4 number combinations are there in 4 numbers?
-- 4 numbers can be lined up in 24 different ways-- If the order doesn't matter, then there's only one4-number combination of 4 numbers.
How many number combinations are possible with three numbers?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
How many 3 number combinations are possible with numbers 1234?
4 of them. In a combination the order of the numbers does not matter.
How many 3 number combinations are possible with 1234?
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
How many different combinations of 6 numbers are there in the numbers 1-45?
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060
How many combinations of six numbers can be had from seven numbers?
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many 2 number combinations can you make with six numbers?
Assuming that the six numbers are different, the answer is 15.
How many times can you get three number combination from six numbers?
You can choose 3 objects from 6 20 ways, assuming order does not matter
How many different combinations of 5 numbers can you get from the numbers 1 -25 with no number repeated in a combination?
To calculate the number of different combinations of 5 numbers chosen from 1 to 25 without repetition, we can use the formula for combinations: nCr = n! / r!(n-r)!. In this case, n = 25 (total numbers) and r = 5 (numbers chosen). Therefore, the number of combinations is 25! / (5!(25-5)!) = 53,130 different combinations.
How many combinations of four numbers are there in 16 numbers?
If order matters and a number cannot be repeated, then there are 16x15x14x13 = 43680 different combinations. If order does not matter then you must divide by the number of ways you can rearrage the same 4 numbers i.e. divide by 4x3x2x1=24 so you can select 4 numbers from a group of 16 in 43680/24 = 1820 ways. In mathematical terms there are 43680 permutations of 16 numbers taken 4 at a time and 1820 combinations of 16 number taken 4 at a time.
