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How many 4 number combinations where the first and last numbers are the same exist?
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How many combinations of 6 numbers are there if you have 10 numbers to choose from?
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
How many 3 number combinations are there from 0-9 and the numbers cannot repeat?
There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.
How many 3 number combinations are their using numbers 0-9?
Well first you will start off with 000, then go up until 999. So there would be 1000 different combinations.
Using 10 numbers how many combinations are there if you can use the same number more than once in the same set?
The first number can be any of the ten, likewise the second and the third so 10 x 10 x 10 = 1000 combinations
How many 2 number combinations are there in the numbers 0 to 9?
100. Don't forget the 00 combination. Otherwise think of all numbers between 1 and 99 with all single digits have a zero in the first column (e.g. 1 = 01) * * * * * No, that is the number of permutations! As far as combinations are concerned, 23 is the same as 32. So, you have 10*9/2 = 45 combinations.
How many combinations of 6 numbers are there if you have 10 numbers to choose from?
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How many 3 number combinations are there from 0-9 and the numbers cannot repeat?
There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.
What is 01 reduce to?
The number 1 is the first whole number of all numbers. It cannot be reduced any lower. There are no other number combinations other that 1 in the number 1.
How many 3 number combinations are their using numbers 0-9?
Well first you will start off with 000, then go up until 999. So there would be 1000 different combinations.
How many combinations are possible with 3 numbers?
I'm assuming they're three unique numbers. Thus, the first can be any of three, the second either of the remaining two, and the last is the last one left. Thus: combinations = 3 * 2 * 1 = 6 Or, more generally, the combinations of n numbers in such a problem is n factorial, denoted as "n!", which is every number from 1 to that number multiplied together.
Using 10 numbers how many combinations are there if you can use the same number more than once in the same set?
The first number can be any of the ten, likewise the second and the third so 10 x 10 x 10 = 1000 combinations
How many 2 number combinations are there in the numbers 0 to 9?
100. Don't forget the 00 combination. Otherwise think of all numbers between 1 and 99 with all single digits have a zero in the first column (e.g. 1 = 01) * * * * * No, that is the number of permutations! As far as combinations are concerned, 23 is the same as 32. So, you have 10*9/2 = 45 combinations.
How many 4 number combinations are there in the numbers 0 to 5?
The first digit can be one of five integers (1 to 5) The second - fourth digits one of six integers (0 to 5). So: number of (valid) combinations is 5*6*6*6=1080 * * * * * This gives the number of permutations, not combinations. I am working on the latter.
If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
Is 495 a perfect number?
No, it isn't. In fact, it is not known whether are odd perfect numbers exist. The first perfect numbers are 6, 28, 496, and 8128.
What 2 numbers have the sum of 70?
There are many combinations of 2 numbers that sum to 70. Any combination of numbers where the first number is x and the second number is 70-x will sum to 70. For example: 69 and 1 68 and 2 67 and 3 66 and 4...
