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A 5-digit combination can be obtained as:
- five 1-digit numbers from 1-9,
- three 1-digit numbers from 1-9 and one 2-digit number from 10-39, or
- one 1-digit number from 1-9 and two 2-digit numbers from 10-39.
There are 9C5 = 126 of the first kind,
9C3*30C1 = 84*30 = 2520 of the second, and 9C1*30C2 = 9*435 = 3915 of the third.
All together, there are 126 + 2520 + 3915 = 6561 5-digit combinations.
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How many 5 digit combinations are there in six digits?
about 1,0000000000000
How many three digit combinations can be made?
To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).
How many 4 digit combinations can be made from 6 digits?
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
How many 6 digit combinations can be made from digits 0 to 9?
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.
What combinations can you make with numbers 1 4 7 2 5 8 0?
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
