3 * 4 * 3 * 2 * 1 = 72;
More than one
18
There are 320 such numbers.
Assuming that leading zeros are not permitted (that is the lowest ten digit number is 1 000 000 000), then there are 4 500 000 000 possible even numbers
There are 41 of them.
6*6*3 = 108 numbers.
More than one
18
Assuming the question refers to the digits 1, 2, ... , 9 the answer is 1344 numbers.
24 of them. So we have a 2 or 6 in the unit position, therefore (2)(4)(3) = 24 even three-digit numbers, can be formed.
There are 320 such numbers.
5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.
The final digit must be a 2 to form an even number. The first digit may be any of three remaining digits (1, 3, 5) while the second digit may be any of the two remaining digits. All together, that makes 3*2 = 6 distinct even numbers.
There are 5760 such numbers.
Assuming that leading zeros are not permitted (that is the lowest ten digit number is 1 000 000 000), then there are 4 500 000 000 possible even numbers
There are 41 of them.
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