There are 5,461,512 such combinations.
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If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
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How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
There are 5,461,512 such combinations.
Oh, what a happy little question! There are 100,000 different 6-digit combinations that can be made from 0 to 99. It's like painting a beautiful landscape with numbers - each combination is unique and special in its own way. Just imagine all the possibilities and let your creativity flow!
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Number of 7 digit combinations out of the 10 one-digit numbers = 120.
There are 9C3 = 84 combinations.
9
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
It depends on how many digit you are choosing from.
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
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