Wiki User
∙ 14y agoThere are 5 choices for every digit.
Each of the first two can be any one of (1, 3, 5, 7, or 9).
Each of the last five can be any one of (2, 4, 6, 8, or 0).
The total number of possibilities is (5 x 5 x 5 x 5 x 5 x 5 x 5) = 57 = 78,125
This is only 0.78125% of the 10 million possible numbers if all 10 digits were allowed in any position.
Wiki User
∙ 14y ago64 if repetition is allowed.24 if repetition is not allowed.
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
125
pizza
Assuming the question refers to the digits 1, 2, ... , 9 the answer is 1344 numbers.
125
There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.
64 if repetition is allowed.24 if repetition is not allowed.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
Order does matter in this case so you need to use the formula for a Permutation with repetition allowed. This would be n^r where n=6 different numbers and r=6 possible places for each number to go when forming the full 6-digit number. 6^6 = 46,656 possible digits
125
pizza
There are 2000 such numbers.
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
2,401
There are 25 such numbers.