0
Since the repetition of digits is not allowed then the number of 7 digit numbers formed = 9 x 9 x 8 x 7 x 6 x 5 x 4 = 544320
Explanation:
The first digit of the number can't be 0 so we have 9 digits to choose from.
And the remaining last places(here 6) can be filled by using the remaining 9 digits i.e. 9P6 = 9!/(9-6)! = 9 x 8 x 7 x 6 x 5 x 4
So, the result is 9 x 9P6 .
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How many different 3 digit house numbers could be made using numerals 4 7 8?
Six.
How many sets of 3 numbers can be made out of 12 different numbers?
You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.
How many sets of 3-digit numbers can be made using 7 numbers and no duplicates within the 3-digit number?
210
How many different 3 digit combinations can be made using numbers one through nine?
Through the magic of perms and coms the answer is 729
How many numbers can you make from 650271 without repeating a digit?
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
If using numbers 1 through 4 how many different 4 digit combinations can be made?
10,000
If using numbers 1 through 8 how many different 4 digit combinations can be made?
15
How many 5 digit numbers can be made using the numbers 37282?
a lot
How many different 3 digit house numbers could be made using numerals 4 7 8?
Six.
How many sets of 3 numbers can be made out of 12 different numbers?
You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.
How many 4 digit numbers can be made by he digits 0123 using the digit once?
2
If using numbers 0 through 9 how many different 4 digit combinations can be made?
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
How many sets of 3-digit numbers can be made using 7 numbers and no duplicates within the 3-digit number?
210
How many different 3 digit combinations can be made using numbers one through nine?
Through the magic of perms and coms the answer is 729
How many two digit numbers can be made using 0-9?
9
How many numbers can you make from 650271 without repeating a digit?
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
