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Eleven.
11
11 with 1 remaining 100 - 1 = 99 = 9 x 11
Of whole numbers only, it's 449. Of all numbers including decimals, it's 449.99999... with the 9s never ending.
Oh, isn't that a happy little question! If we look closely, we can see that there are 20 numbers from 1 to 100 that contain the digit 9. Each of those numbers is like a little friend peeking out from the canvas, adding a touch of joy to our day. So, go ahead and count those 9s with a smile on your face!
99 plus 9/9 = 100
To find the greatest common factor (GCF) of 9s and 63s to the third power, we first need to factor out the common factors of the two numbers. The prime factorization of 9s is 3 * 3 * s, and the prime factorization of 63s^3 is 3 * 3 * 7 * s * s * s. The common factors between the two numbers are 3 * 3 * s, which simplifies to 9s. Therefore, the GCF of 9s and 63s^3 is 9s.
(9*9)+(9+9)+(9/9) = 100
Yes, there are an infinite number of posibilities. Staying only with positive odd numbers, if duplicates are allowed, then five 9s and five 11s make 100. If duplicates are disallowed, then 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 100
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Nine of them
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