111 of them with a remainder of 1
Eleven.
That depends what those nine numbers are. If the numbers are 992, 1, 1, 1, 1, 1, 1, 1, and 1, then it is easy.If the numbers are all 9s, then it can be written 999 + (999 / 999) = 1000.
There are: 640/9 = 71 with a remainder of 1
11 with 1 remaining 100 - 1 = 99 = 9 x 11
999 + (999/999) = 1000
There are: 640/9 = 71 with a remainder of 1
8, remainder 1
1 or 4 , depending on your point of view.
11 with 1 remaining 100 - 1 = 99 = 9 x 11
5
8
Nine of them
Only 1 exists, and it is "999"
The GCF of 9s and 63s^3 is 9s.
10 times
Exactly 6 of them