To find how many times the digit '9' appears from 1 to 1000, we can analyze the occurrences in each digit place: hundreds, tens, and units. In the hundreds place, '9' appears in the range 900-999, contributing 100 occurrences. In the tens place, it appears in the sequences 90-99, 190-199, ..., 990-999, totaling 100 occurrences across those ranges. Lastly, in the units place, it appears in sequences like 9, 19, 29, ..., 999, which also adds up to 100 occurrences. Therefore, the total count of the digit '9' from 1 to 1000 is 300.
111 of them with a remainder of 1
Eleven.
That depends what those nine numbers are. If the numbers are 992, 1, 1, 1, 1, 1, 1, 1, and 1, then it is easy.If the numbers are all 9s, then it can be written 999 + (999 / 999) = 1000.
There are: 640/9 = 71 with a remainder of 1
11 with 1 remaining 100 - 1 = 99 = 9 x 11
111 of them with a remainder of 1
1 ns (nanosecond) = 10-9s 1s / 10-9s = 109 109 = 1000 000 000 1 second = 1000 000 000 ns (nanosecond)
999 + (999/999) = 1000
Eleven.
That depends what those nine numbers are. If the numbers are 992, 1, 1, 1, 1, 1, 1, 1, and 1, then it is easy.If the numbers are all 9s, then it can be written 999 + (999 / 999) = 1000.
There are: 640/9 = 71 with a remainder of 1
8, remainder 1
1 or 4 , depending on your point of view.
11 with 1 remaining 100 - 1 = 99 = 9 x 11
5
Nine of them
79