10 x (70 - 50) = 200 Btu
2250
That will completely depend on how much water there is.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
2250
25
To raise 1 pound of ice from 32°F to water at 32°F it requires 144 BTUs. Since you have 50 pounds of ice, you would need 50 * 144 BTUs to raise the ice to water at 32°F. To further raise the water from 32°F to 160°F, you would need an additional amount of BTUs based on the specific heat capacity of water.
To calculate the BTUs required to raise the temperature of 15 pounds of water, you can use the formula: BTUs = Weight of water in pounds × Temperature change in degrees Fahrenheit × 1 BTU So, the calculation would be: BTUs = 15 lbs × (130°F - 100°F) × 1 BTU = 15 lbs × 30°F = 450 BTUs.
212-65=147. 147(20)=2940 btu needed is this right?
That will completely depend on how much water there is.
To convert 7975 pounds of water weight into degrees, you need to know the temperature in which the water is being measured. Degrees typically refer to temperature, not weight, so more information is needed to provide an accurate conversion.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
How much water? What is the gas used?
It takes 6 SI calories to raise one liter of water by 6 degrees Celsius.
300
It takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Therefore, to raise the temperature of 1 gram of water by 5 degrees Celsius, it would require 5 calories.