Wiki User
∙ 12y agoTo raise the temperature of one cc of water requires i calorie of heat .
you did not specify the volume.
Wiki User
∙ 12y agoheat will flow from the iron to the water until both are the same temperature
100
The specific heat of water is 1 and the heat released is mass x specific heat x the temperature difference, so we have 15 x 1 x 35 = 525 BTU
The idea here is to: * Look up the specific heat of water. * Multiply the mass, times the temperature difference, times the specific heat of water. You may need to do some unit conversions first; specifically, if the specific heat is given per kilogram, you can convert the grams to kilograms.
Heat required for this transition is given as the the sum of three heatsheat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree CelsiusHeating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice=200x0.5x5=500calmelting of ice=mxlatent heat=200x80=16,000calHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5=1000calTotal heat required=500+16,000+1000=17,500 cal
100 degrees celsius are equal to 212 degrees fahrenheit.
When you heat water to 100 degrees Celsius, it boils and turns into steam.
Water boils at 100 degrees Celsius or 212 degrees Fahrenheit.
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
Please try to use your brain to solve simple questions such as this one. The change in temperature is simply 100 - 35 = 65 degrees Celsius.
170o
You can allow hot water to cool or you can heat cold water.
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
heat will flow from the iron to the water until both are the same temperature
100
That depends on the initial temperature of the water and the heating method used. Typically, it would take a few minutes to heat water to 98.6 degrees Fahrenheit on a stovetop or with an electric kettle.
When you heat water to 100 degrees Celsius, it reaches its boiling point and starts to evaporate into steam. Further heating continues to convert more water into steam until all the water has evaporated.