If the sequence of the 3 matters, there are (20 x 19 x 18) = 6,840 ways to line up 3 of 20.
If the sequence of the 3 doesn't matter, there are (6,840/6) = 1,140 unique groups of 3.
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There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.
63
If their sequence matters . . . 120 If it doesn't . . . 20