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How many 5 digit combinations are there from 1 20?
There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.
How many 3 number combinations are there in the numbers 1 - 20?
To calculate the number of 3-number combinations from the numbers 1-20, we can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 20 and r = 3. Plugging these values into the formula, we get 20C3 = 20! / 3!(20-3)! = 1140. Therefore, there are 1140 possible 3-number combinations from the numbers 1-20.
How many combinations of 3 numbers are there in 23 numbers?
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
How many 3 digit combinations are there in 1 to 21?
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
How many 3 number combinations are there from 0-9 and the numbers cannot repeat?
There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.
How many 3 number combinations 1 to 6?
There are 6C3 = 20 such combinations.
How many combinations of 3 things can you make using 4 choices for each thing?
4
How many 5 digit combinations are there from 1 20?
There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.
How many 3 number combinations are there in the numbers 1 - 20?
To calculate the number of 3-number combinations from the numbers 1-20, we can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 20 and r = 3. Plugging these values into the formula, we get 20C3 = 20! / 3!(20-3)! = 1140. Therefore, there are 1140 possible 3-number combinations from the numbers 1-20.
How many combinations of 3 numbers are there in 23 numbers?
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
How many 3 digit combinations are there in 1 to 21?
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
How many five number combinations dose it have in 1 to 20?
The number of combinations is 20C5 = 20!/(15!*5!) = 20*19*18*17*16/(5*4*3*2*1) = 15,504
How do you solve this combinations problem. There are 20 students in one class. They need to form groups of at least 2 people and at most 4 people. In how many different ways can they do that?
Combinations of 2: 20*19/(1*2) = 190 Combinations of 3: 20*19*18/(1*2*3) = 1140 Combinations of 4: 20*19*18*17/(1*2*3*4) = 4845 So 6175 in all.
How many 3 number combinations are there from 0-9 and the numbers cannot repeat?
There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.
What 3 numbers add up to 60?
63
How many different lunch combinations can be made from 2 sandwich choices 3 side items and 3 drinks if you choose one sandwich from each?
2 x 3 x 3 = 18
How many combinations of 1 2 3 is there in 6 runners?
If their sequence matters . . . 120 If it doesn't . . . 20
