Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.
1024
Half of them.
1024 of them.
There are 500 of 3-digit numbers begin with an odd one (100-199, 300-301, 500-599,700-799, and 900-999). In terms of "how many strings of", may filter or expand the above answer.
its 2 raised to power 8 i.e 256
-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.
You are essentially asking how many different bit strings of length 9 are there, as the first 3 bits are fixed. The answer is 2^9 = 512.
Since there are 8 bits in between, and they can assume any of the two values (0 or 1), that results in a total of 28 different combinations.
Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.
1024
210=1024
Half of them.
there are 128 (2 to the power of 7) bit strings of length 7
A parachute needs four strings. However, redundancy is best, both for safety and control of the chute. Thus, 16 striings is better, 32 even moreso. Washers around groups of strings cuts down on the likelihood of entanglement. The length of the strings matters, as well (and so does the diameter of the parachute).
There are no zero-length strings that start with 1 bit or end with 2 bits. In a zero-length string, there are no bits at all.
Five (5) have one or the other but not both. Six (6) have both. Total of eleven (11).